In the given figure, AD is bisector of angle ∠CAB and BD is bisector of angle ∠CBF. If the angle at C is 34^{∘}, the angle ∠ADB is:

This question was previously asked in

SSC CHSL Previous Paper 90 (Held On: 13 Oct 2020 Shift 1)

- 34
^{∘ } - 16
^{∘} - 17
^{∘ } - 32
^{∘ }

Option 3 : 17^{∘ }

**Given:**

AD is bisector of angle ∠CAB.

BD is bisector of angle ∠CBF.

∠ACB = 34°

**Formula:**

If AD is bisector of angle ∠CAB and BD is bisector of angle ∠CBF, then

∠ADB = (1/2) ∠ACB

**Calculatio****n:**

According to the question

∠ADB = (1/2) × 34°

∴ ∠ADB = 17°

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,19,39,349+ Students

Start your FREE coaching now >>

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

[email protected]
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)